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If a number $n$ is divided by $1$, it’s congruent to $0$ (mod 10)

I understand that if $n$ is divided by $1$, it’s congruent to $0$ (mod $10$), but I don’t understand what happens when $n$ is divided by $9$. Do it get anything different? Is it just different, or different to $0$?
$$1 \times 10^0 = 10^0 = 10$$
$$9 \times 10^0 = 10 \times 9^0 = 10 \times 1 = 10$$

A:

You can solve this by doing a straightforward application of a modulo group identity:
$$9\cdot 1 = 0 \mod 10$$
But, there is another approach that would help you. As you have observed, $1\cdot 1=1 \mod{10}$, but
$$9 \cdot 1 = 9 = 1+8 \mod{10}$$
Here, we notice that $9$ and $8$ are relatively prime. So, since $9$ is relatively prime to $10$, it must be that the only way $9$ can be divisible by $10$ is if $9=0$ or $9=10$.
Thus, the formula for your property is just:
$$n = \begin{cases} 0 \mod 10 & n = 0 \\ 10 \mod 10 & n \in \{0,10\} \end{cases}$$
If, however, you had $n\in\{1,9\}$, then $n=9 \mod{10}$, and $n=1 \mod{10}$, respectively.

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Any way to clear last set TimeZone in java?

I have a application where I have to read the meta data of a file using FileInputStream. I had to set the time zone to the system time zone. While reading the meta data I want to delete the time zone set by FileInputStream and set the time zone to the TimeZone.getDefault().
Is there any way to achieve this task in java?

A:

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MSSQL select with multiple records per user and order by id

I am trying to select all the users from my database where all the records per user that are in the database is 5 (total number of records should be 5) and also ordered by the id of each user so they will be on the first page of the query, im having problems to find the correct way to do this, i have been trying using joins but do not know if it is the correct way.
Ex:
SELECT [user].id, [user].name
FROM [us].[dbo].[tblUser]
WHERE user.id IN (SELECT user.id
FROM [us].[dbo].[tblUser] user, [us].[dbo].[tblUser] user1, [us].[dbo].[tblUser] user2, [us].[dbo].[tblUser] user